Download e-book for iPad: A Course in Error-Correcting Codes (EMS Textbooks in by Jørn Justesen and Tom Høholdt

By Jørn Justesen and Tom Høholdt

ISBN-10: 3037190019

ISBN-13: 9783037190012

This publication is written as a textual content for a path aimed toward complicated undergraduates. just some familiarity with hassle-free linear algebra and likelihood is at once assumed, yet a few adulthood is needed. the scholars may possibly focus on discrete arithmetic, computing device technology, or verbal exchange engineering. The ebook can also be an appropriate creation to coding thought for researchers from similar fields or for execs who are looking to complement their theoretical foundation. It provides the coding fundamentals for engaged on initiatives in any of the above components, yet fabric particular to 1 of those fields has no longer been integrated. Chapters hide the codes and interpreting equipment which are at the moment of such a lot curiosity in examine, improvement, and alertness. they offer a comparatively short presentation of the basic effects, emphasizing the interrelations among assorted tools and proofs of all vital effects. a chain of difficulties on the finish of every bankruptcy serves to study the implications and provides the coed an appreciation of the recommendations. furthermore, a few difficulties and recommendations for tasks point out course for extra paintings. The presentation encourages using programming instruments for learning codes, enforcing interpreting tools, and simulating functionality. particular examples of programming workout are supplied at the book's domestic web page. disbursed in the Americas via the yank Mathematical Society.

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Extra info for A Course in Error-Correcting Codes (EMS Textbooks in Mathematics)

Example text

2 have the same order. i j −i j = γ . (You can use the fact that a 2 = b2 ⇒ a = b) 3) Show that γ 2 = γ 2 , j > i ⇒ γ 2 s Let s be the smallest positive number such that γ 2 = γ . 4) Show that γ , γ 2 , . . , γ 2 s−1 are different. 5) Show that g(x) = (x − γ )(x − γ 2 ) · · · (x − γ 2 s−1 ) divides f (x). 6) Show that g(x) ∈ F2 [x]. 7) Show that g(x) = f (x) and hence s = m. 18 1) Determine the number of primitive elements of F32 . 2) Show that the polynomial x 5 + x 2 + 1 is irreducible over F2 .

The subscripts j are called coset representatives. So the above cosets are C0 , C1 , C3 , C5 and C7 . Of course we always have C0 = {0}. It can be seen from the definition that if n = 2m − 1 and we represent a number i as a binary m-vector, then the cyclotomic coset containing i consists of that m-vector and all its cyclic shifts. 6. Suppose n is an odd number, and that the cyclotomic coset C1 has m elements. Let α be a primitive element of F2m and β = α i i∈c j (x − β ). 2m −1 n . Then m β j = 28 Finite fields Proof.

1. Factorization of x n − 1 Input: An odd number n 1. Find the cyclotomic cosets modulo n. 2. Find the number m of elements in C1 . 3. Construct the finite field F2m , select a primitive element α and put β = α 2m −1 n . 4. Calculate f j (x) = (x − β i ), j = 0, 1, . . i∈c j Output: The factors of x n − 1, f 0 (x), f 1 (x), . . One can argue that this is not really an algorithm because in step 3 one needs an irreducible polynomial in F2 [x] of degree m. The table in appendix C not only gives such polynomials up to degree 16, these are also chosen such that they are minimal polynomials of a primitive element.

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A Course in Error-Correcting Codes (EMS Textbooks in Mathematics) by Jørn Justesen and Tom Høholdt

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